pratikum 1 hardiansyah
TRANSCRIPT
x1,2=−b±√b2−4ac
2a
A=[1 23 4 ]
∫1
3
(x2+5 x+6 )dx
f ( x )= x+ log x2❑2
x2+1
TRANSCRIPT
x1,2=−b±√b2−4ac
2a
A=[1 23 4 ]
∫1
3
(x2+5 x+6 )dx
f ( x )= x+ log x2❑2
x2+1