sslc exam- target 40 study notes for revision · pdf file . sslc exam- target 40 study...

SSLC EXAM- TARGET 40 Study notes for Revision 2014
1 Yakub S.,GHS Nada, Belthangady Taluk,D.K. Ph:9008983286 Email: [email protected] For MSTF Mangalore(Belthangady)
1. - : ( : 3)
MCQ 1- 2- 3- 4-
K U A S K U A S K U A S
1 1 2 3
: a = bq + r [ 0 r < ] a , b , q , r
a b ( a, b ) . .. x ( a, b ) . .. = a x b a,b
:
a = bq + r [ 0 r < ] 735 40
40]735 [18 -40 335 -320 15
735 = ( 40 x 18 ) + 15
18 45 . .. . ..
.
18 = 2 x 3 x 3 = 2 x 32
45 = 3 x 3 x 5 = 32 x 5
18 45 . .. = 3 x 3 = 9
18 45 . .. = 3 x 3 x 2 x 5 = 90
120 2 x 2 x 2 x 3 x 5 120
Note: 1 [ : 2 ,3, 5, 7, 11, 13, 17, 19. ]
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-2. (3 )
MCQ 1- 2- 3- 4-
2 1 2 3
U A , B C
: - * .
**
: U = {0,1,2,3,4,5,6,7,8,9}, A={1,2,3,7}, B={3,7,8}, C={1,2,3,8}
Note: A1 = { 0,1,4,5,6,8,9}, B1 = { 0,1,2,4,5,6,9}, C1 = { 0,4,5,6,7,9}
AUB = {1,2,3,7} U {3,7,8} = {1,2,3,7,8}..(1) BUA = {3,7,8} U {1,2,3,7} = {1,2,3,7,8}..(2)
(1) (2) AUB = BUA
AB = {1,2,3,7} {3,7,8} = {3,7} .(1) BA = {3,7,8}{1,2,3,7} = {3,7} ..(2)
(1) (2) , AB = BA
AUB = BUA AB = BA
AU(BUC) = (AUB)UC (AB)C = (ABC)
* AU(BC) = (AUB)(AUC) ** A(BUC) = (AB)U(AC) (AUB)1 = A1B1 (AB)1 = A1UB1
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AU(BUC) = { 1,2,3,7} U [{3,7,8}U{1,2,3,8}] AU(BUC) = { 1,2,3,7} U {1,2,3,7,8} AU(BUC) = {1,2,3,7,8}.. (1) (AUB)UC = [{ 1,2,3,7}U{3,7,8}] U {1,2,3,8} (AUB)UC = { 1,2,3,7,8}U{1,2,3,8} (AUB)UC = { 1,2,3,7,8}.(2)
(1) (2) , AU(BUC)=(AUB)UC
A(BC) = { 1,2,3,7}[{3,7,8}{1,2,3,8}] A(BC) = { 1,2,3,7}{3,8} AU(BUC) = {3}.. (1) (AB)C = [{ 1,2,3,7}{3,7,8}]{1,2,3,8} (AUB)UC = { 3,7}{1,2,3,8} (AB)C = {3}...(2)
(1) (2) , (AB)C= (ABC)
AU(BC) = {1,2,3,7}U[{3,7,8}{1,2,3,8}] AU(BC) = {1,2,3,7}U{3,,8} AU(BC) = {1,2,3,7,8}(1) (AUB)(AUC) = [{1,2,3,7}U{3,7,8}][{1,2,3,7}U{1,2,3,8}] (AUB)(AUC) = {1,2,3,7,8}{1,2,3,7,8} (AUB)(AUC) = {1,2,3,7,8} ..(2)
(1) (2) , AU(BC)=(AUB)(AUC)
A(BUC) = {1,2,3,7}[{3,7,8}U{1,2,3,8}] A(BUC) = {1,2,3,7}{1,2,3,7,8} A(BUC) = {1,2,3,7}(1) (AB)U(AC) = [{1,2,3,7}{3,7,8}]U[{1,2,3,7}{1,2,3,8}] (AB)U(AC) = {3,7}U{1,2,3} (AB)U(AC) = {1,2,3,7}.(2)
(1) (2) , A(BUC)=(AB)U(AC)
(AUB)1 = [{1,2,3,7}U{3,7,8}]1 (AUB)1 = {1,2,3,7,8}1 (AUB)1 = {0,4,5,6,9}..(1) A1B1 = {1,2,3,7,8}1{3,7,8}1 A1B1 = {0,4,5,6,9}{0,1,2,4,5,6,9} A1B1 = {0,4,5,6,9} .. .(2)
(1) (2) (AUB)1 = A1B1
(AB)1 = [{1,2,3,7}{3,7,8}]1 (AB)1 = {3,7}1 (AB)1 = {0,1,2,4,5,6,8,9}..(1) A1UB1 = {1,2,3,7}1U{3,7,8}1 A1UB1 = {0,4,5,6,8,9}U{0,1,2,4,5,6,9} A1UB1 = {0,1,2,3,4,5,6,8,9}..(2)
(1) (2) (AB)1 = A1UB1
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:
,
n(AUB) = n(A) + n(B) n(AUB) = n(A) + n(B) n(AB) A = {0,1,2,3,4}, n(A) = 5 B ={2,3,4,5,6} n(B) = 5, AUB = {0,1,2,3,4,5,6} n(AUB) = 7 AB = {2,3,4} n(AB) = 3 n(AUB) = n(A) + n(B) n(AB) 7 = 5 + 5 3 7 = 10 -3 7 = 7
A = {0,1,2,3,4}, n(A) = 5 B ={2,3,4,5,6} n(B) = 5, AUB = {0,1,2,3,4,5,6} n(AUB) = 7 AB = {2,3,4} n(AB) = 3 n(AUB) = n(A) + n(B) n(AB) 7 = 5 + 5 3 7 = 10 -3 7 = 7
100 ,50
, 25
.
.
?
n(AUB) = n(A) + n(B) n(AB) A { },
B { }
n(A) = 100 , n(B) = 50 , n(AB) = 25 n(AUB) = 100 + 50 25 n(AUB) = 125
50
,42
24
1) 2).
3) .
n(AUB) = n(A) + n(B) n(AB) A { }, B { } n(A) = 50 , n(B) = 42 , n(AB) = 24
= n(AUB) = 50 + 42 24 = 68
= 50-24 =26 , = 42-24=18
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A = { 1,2,3,4,5,6}, B = {1,4,5,7,8 } A\B = {2,3,6}, B\A = {7,8}
AUB AB A1 (AUB)C
A(BUC) A1UB1 A1B1 A\B
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:
MCQ 1- 2- 3- 4-
3 : 1 1 1* 8
:
a, a+d, a+2d, a+3d,,a + (n-1)d a , d
n Tn = a + (n 1)d a , d ,n
Tn+1 = Tn + d d
Tn-1 = Tn d d
,
Tp = Tq + (p-q)d
Tq , d
d =
Tp Tq , d
[T = T T = a ] d =
T - , a , n
n Sn = [ + ( ) ] a , n , d
(a) ( Tn) Sn = [ + ] a , n , T -
n Sn = ( )
n
Note: : .
n , n .
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.
1 n 2n + 3 3 ? T3 = 2x3 + 3 = 6 + 3 = 9
2 Tn = 3n 10 20 ? T20 = 3x20 -10 = 60-10 =50
3 Tn = n3 1, Tn = 26 n = ?
n3 1 = 26 n3 = 26 + 1 n3 = 27, n3 = 33 n = 3
4 Tn = 2n2 + 5 T3 = ? T3 = 2x3
2 + 5 = 2x9 + 5 = 18+5 =23
5 Tn = 5 4n, 3 ? Tn = 5 4x3 = 5 12 = -7
6. Tn = n2 1 Tn+1 =?
Tn+1 = (n+1)2 1 =n2+2n+1-1 = n2+2n OR n(n+2)
7. Tn = n2 + 1 S2 .
Tn = n2 + 1 T1 = 12 +1 = 2, T2 = 22 + 1 = 5 S2 = T1 + T2 = 2 + 5 = 7
..
Tn = a + (n 1)d 1 12,19,26,. T15 . T15 = 12 + (15 1)7 T15 = 12 + 14x7 T15 = 12+ 98 T15 = 110
..
Tn = a + (n 1)d
2 7,13,19, .151 ,
.
a=7, d=6, Tn =151, n=? 151 = 7 + (n 1)6 151 = 7 + 6n 6 151 = 6n + 1 6n = 151 1 6n = 150 n = = 25
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Tn = a + (n 1)d
3 d = -2, T22 = -39, a .
d = -2, T22 = -39, n = 22, a = ? -39 = a + (22 1)-2 -39 = a + 21 x-2 -39 = a - 42 a = -39 + 42 a = 3
4 a = 13, T15 = 55, d = ?
a = 13, T15 = 55, n=15, d = ? 55 = 13 + (15 1)d 55 = 13 + 14d 14d = 55 13 14d = 42 d = , d = 3
Sn = [ + ( ) ] 1 + 4 + 7 .. 21
?
n = 21, a = 1, d = 3,Sn = ? S21 = [2x1 +(21-1)3]
S21 = [2 +20x3] S21 = [2 +60]
S21 = x62 S21 = 21x31 S21 = 651
:
1).3 + 7 + 11 + ----------- 15
:
2).2 + 5 + 8 + ----------------- -- 25
?
:
3).3+ 5 + 7 + ------------ 30
Sn = [ + ] 4 25
76, 25 ?
a = 4, T = 76, n = 25 ,Sn = ? S25 = [4 + 76] S25 = [80] S25 = 25x40 S25 = 1000
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Sn = ( )
1 201 5
.
:
6 200 300
.
5 + 10 + 15 + ------------- + 200 5x1 + 5x2 + 5x3 + --------- + 5x 40 5[1 + 2 + 3 + -----------------40] 5xS40, n = 40 5x ( ) 5x20x41 4100
: , .
n Tn = ( ) a , d ,n
Tn = ( ) , , ------- 21 .
:
, , 1, -1,------- 10 .
T21 = ( )
( )
T3 =
T7 = , T15 .
: T3 = , T7 =
T

sslc exam- target 40 study notes for revision · pdf file . sslc exam- target 40 study...

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