pratikum 1 hardiansyah
Post on 27-Jul-2015
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x1,2=−b±√b2−4ac
2a
A=[1 23 4 ]
∫1
3
(x2+5 x+6 )dx
f ( x )= x+ log x2❑2
x2+1
top related
Post on 27-Jul-2015
29 Views
Preview:
TRANSCRIPT
x1,2=−b±√b2−4ac
2a
A=[1 23 4 ]
∫1
3
(x2+5 x+6 )dx
f ( x )= x+ log x2❑2
x2+1
top related